Garrett Figueroa · @djspacewhale
37 followers · 275 posts · Server mathstodon.xyz

I **think** I've got a good proof that "every nonempty set has a group structure" -> , but I'd like to run it by the community. in particular, I'm not using the Hartogs number anywhere, and I'm not finding my proof in my brief Google search, so I'd like a sanity check on this.

well, let's look at a family of nonempty sets \( \{A_i\}_{i \in I} \), WTS \( \prod_I A_i \) is nonempty. each of the \( A_i \)'s has a group structure, heck, let's name it \( A'_i \) perhaps, and look at the product group \( \prod_I A'_i \) (here's the step where I feel slightly queasy, but since group products are fine constructively (or at least in Agda), I think it's ok...). but now, \( \prod_I A'_i \) has as its underlying set \( \prod_I A_i \), and by our group structure (and slight abuse of notation) this set is pointed by the identity element \( (e_i)_{i \in I} \in \prod_I A_i \) and we're done (?)

#axiomofchoice #constructivemath

Last updated 2 years ago

Nishar · @nishararjyal27
28 followers · 17 posts · Server mathstodon.xyz
xameer :qed: · @xameer
94 followers · 159 posts · Server mathstodon.xyz
JordiGH · @JordiGH
709 followers · 20515 posts · Server mathstodon.xyz

Whenever I read mathematics, no matter what kind it is, I always think that I don't understand it unless I could, in principle, teach a computer how to perform it.

I'm not exactly an intuitionist, but this attitude of mine does mean that I don't like the very much. What good are objects that are literally undescribable?

The only solution around that is to mechanise the instead of the mathematics and that always feels so unsatisfying and distanced to me.

#metamathematics #axiomofchoice

Last updated 7 years ago