How to prove this?!🤔

\[\displaystyle\int_\tfrac{1}{2}^1\dfrac{\psi(x)}{1+\Gamma^2(x)}dx=\ln\left(\sqrt{\dfrac{1+\pi}{2\pi}}\right)\]

where \(\Gamma(x)\) and \(\psi(x)\) are the gamma and digamma functions respectively.

#logarithm #pi #digammafunction #gammafunction #definiteintegral #integral

Last updated 3 years ago